Physics
posted by Sydney .
Suppose two boxes on a frictionless table are connected by a heavy cord of mass 1.0 kg. Calculate the acceleration (magnitude) of each box and the tension (magnitude) at each end of the cored, using the freebody diagrams shown in Figure 453. Assume FP = 44.0 N, ma = 11.0 kg, and mb = 13.5 kg, and ignore sagging of the cord. Compare your results to Example 412 and Figure 422.
mA acceleration ____ m/s2
mB acceleration ____ m/s2
FTA ____ N
FTB ____ N

If you treat the whole system as one solid thing, you will get the answer.
FP= mtotal x acceleration
44= (11+13.5+1)a
44=25.5a
a=1.73m/s^2
Use this acceleration value to find FTA and FTB using Newton's 2nd Law.
FBT=13 x 1.73
FBT= 22.5 N
(FBT and FTB are equal in magnitude)
and
44FAT=11 x 1.73
44FAT=19.03
FAT=4419.03
FAT=25.0 N