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Posted by **Brianna** on Thursday, October 13, 2011 at 8:58pm.

B. In part A, could you solve the problem by letting n= the middle integer,n-1= the smallest integer, and n+1= the largest integer?

- Algebra -
**bobpursley**, Thursday, October 13, 2011 at 9:04pmn+n+1+ n+2=126

3n=126-3

n=41, next 42,next 43

yes, you can do it that way.

N-1+n+n+1=`26

3n=126

n=42

so numbers are 41,42,43

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