Posted by **Brianna** on Thursday, October 13, 2011 at 8:49pm.

A jet leaves the Charlotte, North Carolina, airport traveling at an average rate of 564 km/h. Another jet leaves the airport one half hour later traveling at 744km/h in the same direction. Use an equation to find how long the second jet will take to overtake the first.

- Algebra -
**Steve**, Friday, October 14, 2011 at 11:22am
at time t hr, the first plane goes 564t km

the second jet flies for 1/2 hour less, but at 744 km/h, so it has gone 744(t-.5)

When they have both gone the same distance,

744(t-.5) = 564t

744t - 372 = 564t

180t = 372

t = 2 hr 4 min

## Answer This Question

## Related Questions

- Algebra - A jet leaves the Charlotte, North Carolina, airport traveling at an ...
- Math - a jet leaves the Charlotte, North Carolina, airport traveling at an ...
- Algebra1 - A jet leaves the airport traveling at an average rate of 564km/h. ...
- Pre-Algebra - A Jet airplane leaves an airport traveling at a steady rate of ...
- Math - A jet leaves an airport traveling at a steady rate of 600 km/h. Another ...
- algebra - Jet #1 leaves an airport at 600 km/h. Jet #2 leaves 3/4 hour after jet...
- Algebra - An ordinary plane leaves an airport and flies due west at 180kph. Two ...
- algebra - A private plane leaves an airport and flies due east at 192 miles per ...
- Marh - An ordinary plane leaves an airport and flies due west at 180kph. Two ...
- Math - An ordinary plane leaves an airport and flies due west at 180kph. Two ...

More Related Questions