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March 31, 2015

March 31, 2015

Posted by **jen** on Thursday, October 13, 2011 at 7:49pm.

(a) Find the velocity of the ball 5 seconds after it is thrown. 1 m/s.

(b) Find the velocity of the ball 10 seconds after it is thrown. 2 m/s.

(c) How high does it rise above the edge of the cliff (from where it was thrown)? 3 m.

- math -
**Damon**, Thursday, October 13, 2011 at 7:59pmcall g = -10m/s^2

v = vi - g t = +60 - 10t

when t = 5

v = 60 -10(5) = 10 m/s

when t = 10

v = 60 - 10 (10) = -40 m/s

y = yi + vi t - (1/2)g t^2

what is t at the top where v = 0 ??

0 = 60 - 10 t

t = 6 seconds to top

y = 0 + 60(6) -5 (36)

= 180

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