A basket contains 11 pieces of fruit: 4 apples, 5 oranges, and 2 bananas. Jonas takes a piece of fruit at random from the basket, and then Beth takes a piece at random. What is the probability that Jonas will get an orange and Beth will get an apple?
I will assume that the order of Jonas picking, then Beth is important.
so prob(as stated) = (5/11)(4/10) = 2/11
its wrong yall aint no help
To solve this problem, we need to determine the total number of possible outcomes and the number of outcomes where Jonas gets an orange and Beth gets an apple.
First, let's find the total number of possible outcomes. To do this, we need to consider that Jonas and Beth can each select one piece of fruit. Thus, the total number of possible outcomes is the product of the number of fruit choices for Jonas and Beth.
The number of fruit choices for Jonas is 11 since there are 11 pieces of fruit in the basket. After Jonas takes a piece of fruit, there are 10 remaining pieces of fruit for Beth to choose from. Therefore, the number of fruit choices for Beth is 10.
So, the total number of possible outcomes is 11 * 10 = 110.
Next, let's determine the number of outcomes where Jonas gets an orange and Beth gets an apple. Jonas can choose from 5 oranges, and Beth can choose from 4 apples since there are 5 oranges and 4 apples in the basket.
Therefore, the number of outcomes where Jonas gets an orange and Beth gets an apple is 5 * 4 = 20.
Finally, to find the probability of this event occurring, we divide the number of successful outcomes (where Jonas gets an orange and Beth gets an apple) by the total number of possible outcomes:
Probability = Number of successful outcomes / Total number of possible outcomes = 20 / 110 ≈ 0.182 (rounded to three decimal places)
So, the probability that Jonas will get an orange and Beth will get an apple is approximately 0.182 or 18.2%.