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Posted by on Thursday, October 13, 2011 at 4:53pm.

Use the table below to find the products of the two polynomials. Enter your answer in descending order in the box below. Enter exponents using the caret ( ^ ). For example, you would enter as 4x^2. Do not enter spaces in your answer.

(x3 + 2x2 - 2)(x3 - 3x + 3)how do you do this?

  • algebra 1b - , Thursday, October 13, 2011 at 5:17pm

    Just multiply term by term, just as you do with a multi-digit number:

    124* 327 = 100(300+20+7) + 20(300+20+7) + 4(300+20+7)

    (x^3 + 2x^2 - 2)(x^3 - 3x + 3)
    = x^3(x^3 - 3x + 3) + 2x^2(x^3 - 3x + 3) - 2(x^3 - 3x + 3)

    = x^6 - 3x^4 + 3x^3 + 2x^5 - 6x^3 + 6x^2 - 2x^3 + 6x - 6

    = x^6 + 2x^5 - 3x^4 - 5x^3 + 6x^2 + 12x - 6

  • algebra 1b - , Thursday, October 13, 2011 at 5:18pm

    Ahem. Make that + 6x

  • algebra 1b - , Thursday, October 13, 2011 at 5:21pm

    thanks :)

  • algebra 1b - , Thursday, October 13, 2011 at 5:23pm

    (x7 + x4 + x)(x3 - 1)
    can u help me with this one 2

  • algebra 1b - , Thursday, October 13, 2011 at 5:25pm

    it was wrong the first one

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