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December 21, 2014

December 21, 2014

Posted by **sam** on Thursday, October 13, 2011 at 4:53pm.

(x3 + 2x2 - 2)(x3 - 3x + 3)how do you do this?

- algebra 1b -
**Steve**, Thursday, October 13, 2011 at 5:17pmJust multiply term by term, just as you do with a multi-digit number:

124* 327 = 100(300+20+7) + 20(300+20+7) + 4(300+20+7)

(x^3 + 2x^2 - 2)(x^3 - 3x + 3)

= x^3(x^3 - 3x + 3) + 2x^2(x^3 - 3x + 3) - 2(x^3 - 3x + 3)

= x^6 - 3x^4 + 3x^3 + 2x^5 - 6x^3 + 6x^2 - 2x^3 + 6x - 6

= x^6 + 2x^5 - 3x^4 - 5x^3 + 6x^2 + 12x - 6

- algebra 1b -
**Steve**, Thursday, October 13, 2011 at 5:18pmAhem. Make that + 6x

- algebra 1b -
**sam**, Thursday, October 13, 2011 at 5:21pmthanks :)

- algebra 1b -
**sam**, Thursday, October 13, 2011 at 5:23pm(x7 + x4 + x)(x3 - 1)

can u help me with this one 2

- algebra 1b -
**sam**, Thursday, October 13, 2011 at 5:25pmit was wrong the first one

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