Posted by joe on Thursday, October 13, 2011 at 2:46pm.
Well, we don't have a diagram, but that won't stop us in this case. A midsegment of a triangle is parallel to one of the sides, and half its length.
Since de=7 is not half of ab=10, nor of bd=13, then that means that it must be half of ac. So, ac=14, and the perimeter is
p = 10 + 13 + 14 = 37
joel
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