Posted by Lorie on Thursday, October 13, 2011 at 1:50pm.
Here is one formula you might use for this problem:
n = [(z-value)^2 * p * q]/E^2
With your data:
n = [(1.96)^2 * .5 * .5]/.10^2
I'll let you finish the calculation (round to the next highest whole number).
Note: n = sample size needed; .5 for best estimate of the population proportion; .5 for q, which is (1 - p). E = maximum error, which is 10% or .10 from the problem. Z-value is found using a z-table (for 95%, the value is 1.96).
I hope this helps.
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