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April 19, 2014

April 19, 2014

Posted by **Lorie** on Thursday, October 13, 2011 at 1:50pm.

- Statistics -
**MathGuru**, Friday, October 14, 2011 at 6:00pmHere is one formula you might use for this problem:

n = [(z-value)^2 * p * q]/E^2

With your data:

n = [(1.96)^2 * .5 * .5]/.10^2

I'll let you finish the calculation (round to the next highest whole number).

Note: n = sample size needed; .5 for best estimate of the population proportion; .5 for q, which is (1 - p). E = maximum error, which is 10% or .10 from the problem. Z-value is found using a z-table (for 95%, the value is 1.96).

I hope this helps.

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