Posted by **Lorie** on Thursday, October 13, 2011 at 1:49pm.

A private medical clinic wants to estimate the true mean annual income of its patients. The clinic needs to be within $500 of the true mean. The clinic estimates that the true population standard deviation is around $2,300. If the confidence level is 95%, find the required sample size in order to meet the desired accuracy.

- Statistics -
**MathGuru**, Friday, October 14, 2011 at 6:09pm
Formula:

n = [(z-value * sd)/E]^2

...where n = sample size, z-value will be 1.96 for 95% interval, sd = 2300, E = 500, ^2 means squared, and * means to multiply.

Plug the values into the formula and finish the calculation. Round your answer to the next highest whole number.

- Statistics -
**missy**, Sunday, August 26, 2012 at 1:42pm
82

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