Posted by Sierra on Thursday, October 13, 2011 at 10:39am.
In solving the equation (x + 3)(x + 1) = 48, Eric stated that the solution would be
x + 3 = 48 => x = 45
or
(x + 1) = 48 => x = 47
However, at least one of these solutions fails to work when substituted back into the original equation. Why is that? Please help Eric to understand better; solve the problem yourself, and explain your reasoning.

Algebra  Anonymous, Thursday, October 13, 2011 at 11:42am
It doesn't work because if we assume:
x+3 = 48
we fail to take into account the x+1 expression.
However, if we had the equation (x+3)(x+1) = 0, then we can set x+3 = 0

Algebra  Steve, Thursday, October 13, 2011 at 4:26pm
It doesn't work because
ab = 48 does not mean that one or the other is 48.
However, if ab=0, then one or the other must be 0.
Answer This Question
Related Questions
 algebra  1. In solving the equation (x + 3)(x + 1) = 48, Eric stated that the ...
 intermediate algebra  In solving the equation (x1)(x+2)=30. Eric stated that ...
 algebra  solving the equation (x+4)(x4)=9 Eric stated that the solution would ...
 math  In solving the equation (x + 4)(x – 7) = 18, Eric stated that the ...
 algbera  In solving the equation (x + 3)(x + 1) = 48, Eric stated that the ...
 South  In solving the equation (x + 1)(x – 2) = 54, Eric stated that the ...
 intermediate algebra  in solving the equation (x+4)(x4)=9 eric stated the ...
 algebra  in solving the equation (x +2)(x  2) = 32 eric stated the solution to...
 Math  I don't understand how to solve this problem: In solving the equation (x...
 Math  In solving the eqaution(x+4)(x4),Eric stated thatthe solution would be x...
More Related Questions