Posted by **Christina** on Thursday, October 13, 2011 at 10:21am.

What is the standard form of the equation of the line passing through the point (-1,-2) and perpendicular to the line y= - 2/3x - 1?

a. 3x-2y=-1

b.3x-2y=1

c.3x+2y=1

d.3x+2y=-1

I don't understand, can anyone help me please?

- Algebra -
**Christina**, Thursday, October 13, 2011 at 10:36am
Would this be B?

3(-1) - 2(-2) = 1

(-3) - (-4) =1

1 = 1

- Algebra -
**Steve**, Thursday, October 13, 2011 at 4:23pm
Yes.

However, I don't think you understand why. Just checking to see which of the lines contains your point is not enough.

The line y = -2/3x - 1 has slope -2/3.

Any line perpendicular to that line has slope -1/(-2/3) = 3/2.

So, now you have a slope and a point.

Using the point-slope form a line,

y-(-2) = 3/2 (x-(-1))

y+2 = 3/2 (x+1)

2(y+2) = 3(x+1)

2y + 4 = 3x + 3

3x - 2y = 1

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