Posted by Christina on Thursday, October 13, 2011 at 10:21am.
What is the standard form of the equation of the line passing through the point (-1,-2) and perpendicular to the line y= - 2/3x - 1?
I don't understand, can anyone help me please?
- Algebra - Christina, Thursday, October 13, 2011 at 10:36am
Would this be B?
3(-1) - 2(-2) = 1
(-3) - (-4) =1
1 = 1
- Algebra - Steve, Thursday, October 13, 2011 at 4:23pm
However, I don't think you understand why. Just checking to see which of the lines contains your point is not enough.
The line y = -2/3x - 1 has slope -2/3.
Any line perpendicular to that line has slope -1/(-2/3) = 3/2.
So, now you have a slope and a point.
Using the point-slope form a line,
y-(-2) = 3/2 (x-(-1))
y+2 = 3/2 (x+1)
2(y+2) = 3(x+1)
2y + 4 = 3x + 3
3x - 2y = 1
Answer this Question
More Related Questions
- Math - Write your answer in standard form. Show all your work if you want to be ...
- Pre- Algebra - Given an equation of a line, how do I find equations for lines ...
- math - i have more than one question so if u no any of the answers please tell ...
- algebra - Could you please help me?? point-slope form linear equation y-3 = 3(x+...
- Algebra - Write an equation in standard form (slope-intecept form) of the line ...
- Algebra 1 - Write an equation in slope-intercept form for a line that passes ...
- algebra - Please help me. Find the equation of the line satisfying the ...
- Algebra - Find the equation, in standard form, with all integer coefficients, of...
- algebra - Write the equation of the line that passes through point (5, 4) with a...
- Algebra... - Write the equation of a vertical line passing through the point (8...