Posted by **Rebecca** on Thursday, October 13, 2011 at 9:10am.

One zero of f(x)=x^3+4x^2+x+c is -3.

a) calculate the value of c.

b)calculate the other zeros.

- Grade 12 Advanced Functions -
**Anonymous**, Thursday, October 13, 2011 at 10:14am
Ummm, didn't MathMate just do one of these for you? Plug in -3 and evaluate to find c.

- Grade 12 Advanced Functions -
**Anonymous**, Thursday, October 13, 2011 at 10:43am
Ummmmm, I needed help with the second part

- Grade 12 Advanced Functions -
**Steve**, Thursday, October 13, 2011 at 10:48am
Divide by x+3 and see what you get:

x^3 + 4x^2 + x -6

= (x+3)(x^2 + x - 2)

= (x+3)(x+2)(x-1)

Got it now?

- Grade 12 Advanced Functions -
**Confused**, Thursday, October 13, 2011 at 6:09pm
what about this question:

Determine the roots algebraically by factoring.

a) x^3-8x^2-3x+90=0

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