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July 30, 2014

July 30, 2014

Posted by **Rebecca** on Thursday, October 13, 2011 at 8:54am.

- Grade 12 Advanced Functions -
**MathMate**, Thursday, October 13, 2011 at 9:01amP(x)=2x^3+px^2-x+6 = (x-2)Q(x)=0

Since (x-2) is a factor of P(x), evalulate P(2) and equate the result to zero:

2(2)^3+p(2)^2-(2)+6 = 0

16+4p-2+6=0

4p=-20

p=-5

- Grade 12 Advanced Functions -
**Rebecca**, Thursday, October 13, 2011 at 9:11amThank you!!!!

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