Posted by aichan on Thursday, October 13, 2011 at 8:15am.
Two equal charges are separated by 3.7 x 10^10 m. The force between the charges has a magnitude of 2.37 x 10^3 N. What is the magnitude of q on the charges?
can some one explain to me how to do this step by step. Not that great at math hope you can help. Thanks

Physics  drwls, Thursday, October 13, 2011 at 9:01am
There is a formula for the force (F) between two charges (Q1 and Q2), separated by a distance R. It is called Coulomb's Law. It must be in your text or notes; otherwise they would not have assigned this problem.
The formula says
F = k Q1*Q2/R^2
where k is a constant that equals 8.99*10^9 N*m^2/C^2
In your case, Q1 = Q2 = q, so
F = k*q^2/R^2
Rearrange the equation algebraically and solve for q
q = R sqrt(F/k)= 3.7*10^10m*sqrt(2.636*10^13)M/m
= 1.9*10^16 Coulombs

Physics  aichan, Thursday, October 13, 2011 at 10:12am
Thanks!

Physics (typo correction)  drwls, Thursday, October 13, 2011 at 10:45am
q = R sqrt(F/k)
= 3.7*10^10m*sqrt(2.636*10^13)C/m
C stands for Coulombs
I typed M where it should be C
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