five hundred kcal of heat is added to 2-kg of water at 80 degree Celsius. how much steam is produced?
First, you need to transfer 2*1.0*20 = 40 kcal to heat the 2kg 20 degrees to the boiling point. That leaves 460 kcal for vaporization.
Amount of steam produced = (460 cal)/(540 kcal/kg) = 0.852 kg
No idea
Well, that's a hot one! To figure out how much steam is produced, we first need to determine how much heat energy is required to convert water at 80 degrees Celsius into steam. This is what we call the latent heat of vaporization.
For water, the latent heat of vaporization is approximately 2260 kJ/kg. Since we know that 500 kcal (or 500,000 cal) of heat is added, we need to convert it into kJ by dividing it by 4.184 (since there are 4.184 joules in 1 calorie).
So, 500,000 cal ÷ 4.184 = approximately 119,571 kJ.
Now that we have the amount of heat energy, we can calculate the amount of steam produced. This can be done by dividing the amount of heat energy by the latent heat of vaporization:
119,571 kJ ÷ 2260 kJ/kg = approximately 52.9 kg of steam.
So, adding 500 kcal of heat to 2 kg of water at 80 degrees Celsius would produce approximately 52.9 kg of steam. That's steam-tastic!
To find out how much steam is produced when 500 kcal of heat is added to 2 kg of water at 80 degrees Celsius, we need to follow these steps:
Step 1: Determine the initial temperature
The initial temperature of the water is given as 80 degrees Celsius.
Step 2: Calculate the heat absorbed by the water
The specific heat capacity of water is 1 calorie per gram per degree Celsius, or 1 kcal per kg per degree Celsius.
Heat absorbed by the water = (mass of water) * (specific heat capacity of water) * (change in temperature)
= 2 kg * 1 kcal/kg/°C * (100°C - 80°C)
= 2 kg * 20 kcal/°C
= 40 kcal
Step 3: Calculate the remaining heat energy used to convert water to steam
The heat of vaporization of water is 540 kcal/kg.
Remaining heat energy = Total heat added - Heat absorbed by water
= 500 kcal - 40 kcal
= 460 kcal
Step 4: Calculate the mass of steam produced
Mass of steam produced = Remaining heat energy / Heat of vaporization of water
= 460 kcal / 540 kcal/kg
≈ 0.852 kg
Therefore, approximately 0.852 kg of steam is produced when 500 kcal of heat is added to 2 kg of water at 80 degrees Celsius.
To determine how much steam is produced when 500 kcal of heat is added to 2 kg of water at 80 degrees Celsius, we need to consider the process of phase change.
First, we should calculate the amount of heat needed to raise the temperature of water from 80 degrees Celsius to its boiling point (100 degrees Celsius). The specific heat capacity of water is approximately 1 calorie per gram per degree Celsius. To convert kcal to calories, we multiply by 1000 since 1 kcal = 1000 calories.
Heat energy = mass × specific heat capacity × temperature change
Temperature change = 100 - 80 = 20 degrees Celsius
Heat energy for raising the temperature = 2 kg × 1000 g/kg × 1 cal/g°C × 20°C = 40,000 calories
Next, we should calculate the heat energy needed to convert water at 100 degrees Celsius into steam at 100 degrees Celsius. This is known as the latent heat of vaporization for water, which is approximately 540 calories per gram.
Heat energy for phase change (water to steam) = mass × latent heat of vaporization
Mass of water = 2 kg × 1000 g/kg = 2000 grams
Heat energy for phase change = 2000 g × 540 cal/g = 1,080,000 calories
Now, we can calculate the total heat energy required:
Total heat energy = heat energy for raising temperature + heat energy for phase change
= 40,000 calories + 1,080,000 calories
= 1,120,000 calories
Since we want to convert this value to kcal, we divide by 1000:
Total heat energy = 1,120,000 / 1000 = 1120 kcal
From our initial information, we know that 500 kcal of heat is added. Therefore, we have:
Steam produced = Total heat energy added - Heat energy for raising the temperature
= 1120 kcal - 500 kcal
= 620 kcal
In conclusion, 500 kcal of heat added will produce approximately 620 kcal of steam.