Posted by James on Thursday, October 13, 2011 at 12:50am.
you are driving a 2520.0kg car at a constant speed of 14.0 m/s along a wet, but straight, level road. As you approach an intersection, the traffic light turns red. You slam on the brakes. The car's wheels lock, the tires begin skidding, and the car slides to a halt in a distance of 25.8 m. What is the coefficient of kinetic friction between your tires and the wet road?

physics  Henry, Friday, October 14, 2011 at 7:45pm
Wc = ma = 2520kg * 9.8N/kg = 24,696N =
Weight of car.
Fc = (24,696N.,0 deg.).
Fv = 24,696cos(0) = 24,696N. = Force perpendicular to road.
a = (Vf^2  Vo^2) / 2d,
a = (0  (14)^2) / 51.6 = 3.8m/s^2.
Fn = ma = 2520 * (3.8) = 9572N.
Ff = u*Fv = (9572),
24,696u = 9572,
u = 0.388. = Coefficient of friction.
Answer This Question
Related Questions
 Physics  You are driving a 2520.0kg car at a constant speed of 14.0 m/s along ...
 Physics  You are driving a 2530.0kg car at a constant speed of 14.0 m/s along ...
 Physics  You are driving a 2570.0kg car at a constant speed of 14.0 m/s along ...
 Physics  You are driving a 2570.0kg car at a constant speed of 14.0 m/s along ...
 Physics  You are driving a 2570.0kg car at a constant speed of 14.0 m/s along ...
 Phyics  You are driving a 2520.0 kg car at a constant speed of 14.0 m/s along ...
 Physics  You are driving a 2590.0 kg car at a constant speed of 14.0 m/s along ...
 physics9  You are driving a 2460.0kg car at a constant speed of 19.0 m/s along...
 Physics  You are driving a 2475.0 kg car at a constant speed of 10.0 m/s along ...
 Physics  You are driving 2500 Kg car at a constant speed of 14 m/s along an icy...
More Related Questions