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March 29, 2015

March 29, 2015

Posted by **James** on Thursday, October 13, 2011 at 12:50am.

- physics -
**Henry**, Friday, October 14, 2011 at 7:45pmWc = ma = 2520kg * 9.8N/kg = 24,696N =

Weight of car.

Fc = (24,696N.,0 deg.).

Fv = 24,696cos(0) = 24,696N. = Force perpendicular to road.

a = (Vf^2 - Vo^2) / 2d,

a = (0 - (14)^2) / 51.6 = -3.8m/s^2.

Fn = ma = 2520 * (-3.8) = -9572N.

Ff = u*Fv = -(-9572),

24,696u = 9572,

u = 0.388. = Coefficient of friction.

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