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October 21, 2014

October 21, 2014

Posted by **Nadia** on Wednesday, October 12, 2011 at 11:36pm.

- Algebra-HELP -
**MathMate**, Wednesday, October 12, 2011 at 11:40pmy=f(x)=x^2-x-6

The y-intercept is the value of y when x=0.

Substitute x=0 in the above equation to find the y-intercept.

The x-intercept is to find the roots of the equation, when y=0, or

f(x)=x^2-x-6=0

By factoring f(x) into

f(x)=(x-3)(x+2)

you should be able readily find the two zeroes of f(x).

If you need further help, post again.

- Algebra-HELP -
**Nadia**, Wednesday, October 12, 2011 at 11:47pmwell i know the x-intercept is (3,-2)

but i can seem to understand y intercept. I thought it would be (0,0) but it was wrong

- Algebra-HELP -
**Steve**, Thursday, October 13, 2011 at 4:42amThe y-intercept is where the graph crosses the y-axis, that is, where x=0.

In this case, f(0) = 0 - 0 - 6 = -6, so the y-intercept is (0,-6)

- Algebra-HELP -
**Steve**, Thursday, October 13, 2011 at 4:43amAlso, there are two x-intercepts: (3,0) and (-2,0). They are the points where the graph crosses the x-axis, not just the x-values.

- Algebra-HELP -
**Nadia**, Thursday, October 13, 2011 at 7:14amThank you!!

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