Posted by A person on Wednesday, October 12, 2011 at 11:20pm.
CH3COOH we will call HAc
100 mL x 0.017 = 1.7 millimoles HAc
10 mL x 0.026 = 0.25 mmoles NaOH.
...........HAc + NaOH ==> NaAx + H2O
initial....1.7....25.......0......0
change....-.25..-0.25......0.25
equil.....1.45.....0........0.25
concn acid = 1.45 mmoles/(100+10)mL=?
concn Ac^- = 0.25/110 = ?
(H^+)(Ac^-)/(HAc) - Ka
Substitute Ac from above and HAc from above and solve for H^+, then convert to pH.
68.0 mL is the equivalence point so pH is determined by hydrolysis of the salt and concn of salt (Ac^-) = 1.7 mmols/168 mL = ?
...........Ac^- + HOH ==> HAc + OH^-
initial...1.7/168..........0.....0
change......-x.............x......x
equil.....you do it........x.......x
Kb = (Kw/Ka) = (x)(x)/(Ac^-)
Substitute Kw, Ka, and Ac^- and solve for x which = OH^-, I would convert to pOH, then to pH.
After 100 mL, you have an excess of OH which is a strong base and pH is determined from the excess of OH added. Don't forget that the total volume will be 200 mL.
Related Questions
chemistry - Hello, im having major issues with this problem...A 100.0-mL ...
chemistry - hi im having problems figuring this out. consider the titration of ...
Chemistry - "Find the pH of the solution obtained when 32 mL of 0.087 M ...
Chemistry - A buffer solution of volume 100.0 mL is 0.150 M Na2HPO4(aq) and 0....
chemistry - if the pH of a half-neutralized acid solution is 5.4, how would you ...
Chemistry - I need major help with this problem! especially with the first ...
Chemistry - can anyone help me with this question A solution is made by ...
Chemistry DrBob - What is the pH of the solution created by combining 2.30 mL of...
Chemistry - You made 100.0 ml of a lead (II) nitrate solution for lab but forgot...
chemistry - If 100 mL of .03 M HCL solution is added to 100 mL of buffer ...
For Further Reading