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February 28, 2015

Posted by **Ty** on Wednesday, October 12, 2011 at 8:49pm.

- Math WORD PROBLEM -
**bobpursley**, Wednesday, October 12, 2011 at 8:52pmT1= r1/r2 * V2/V1

T1= (1700+3960)/(860+3960) * 34000/27000

- Math WORD PROBLEM -
**tchrwill**, Thursday, October 13, 2011 at 10:33amThe actual velocity of a satellite orbiting at 860 miles altitude is 24,113 fps.

The period derives from

T = 2(Pi)sqrt(r^3/µ) = 113.3 minutes.

The actual velocity of a satellite orbiting at 1700 miles altitude is 21,705 fps.

The period derives from

T = 2(Pi)sqrt(r^3/µ) = 144.18 minutes.

Alternatively,

T2/T1 = sqrt[(r2)^3/(r1)^3]

or T2/T1 =sqrt[5660^3/4820)^3]=1.272489

T2 = 113.3(1.272489) = 144.18

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