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December 20, 2014

December 20, 2014

Posted by **Andres** on Wednesday, October 12, 2011 at 7:10pm.

f(x)=3x^5-5x^4-80x^3+360x^2+1000x+850

- Calc -
**Steve**, Wednesday, October 12, 2011 at 7:58pminflection at y'' = 0

y' = 15x^4 - 20x^3 - 240x^2 + 720x + 1000

y'' = 60x^3 - 60x^2 - 480x + 720

so solve y'' = 0

x^3 - x^2 - 8x + 12 = 0

(x-2)(x-2)(x+3) = 0

There you have the x values. I trust you can evaluate y(x) to get the rest.

- Calc -
**Andres**, Wednesday, October 12, 2011 at 8:01pmso would the inflection point be x=-3 because thats where it goes from decreasing to increasing

- Calc -
**in the same class**, Wednesday, October 12, 2011 at 9:56pmyes

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