Posted by Hannah on .
A sample of 30.0 mL of sulfuric acid solution was titrated with 0.720 M KOH. It was found that 46.9 mL of the base was needed to neutralize the acid. What is [H2SO4]?
would you do (30.0)(0.720) / 46.9 ?
2KOH + H2SO4 ==> K2SO4 + 2H2O
moles KOH = M x L = 0.0469 x 0.720
mols H2SO4 = 1/2 that from the equation.
M H2SO4 = moles H2SO4/L H2SO4. Solve for L and convert to mL.