posted by Eddie on .
Janet jumps off a high-diving platform with a horizontal velocity of 3.5 m/s and lands in the water 1.7 s later. How high is the platform, and how far from the base of the platform does she land?
When finding how high the platform is the horizontal velocity isn't important.
S= 1/2at^2 where S is the displacement and a is the acceleration due to gravity (9.8)
S=(1/2) (9.8) 1.7^2
When finding how far from the base Janet lands use the formula:
D=Ut where D= the distance from the platform, U= the horizontal velocity, and t= time
Simple isn't it?
Janet jumps off a high diving platform with a horizontal velocity of 2.64 m/s and lands in the water 2.8 s later. How high is the platform? The acceleration of gravity is 9.8^2 m/s. Answer in units of m