Post a New Question

physics

posted by on .

Janet jumps off a high-diving platform with a horizontal velocity of 3.5 m/s and lands in the water 1.7 s later. How high is the platform, and how far from the base of the platform does she land?

  • Physics - ,

    When finding how high the platform is the horizontal velocity isn't important.
    S= 1/2at^2 where S is the displacement and a is the acceleration due to gravity (9.8)
    so
    S=(1/2) (9.8) 1.7^2
    S=4.9*1.7^2
    S=14.161 meters

    When finding how far from the base Janet lands use the formula:
    D=Ut where D= the distance from the platform, U= the horizontal velocity, and t= time
    So:
    D=Ut
    D=3.5*(1.7)
    D=5.95
    Simple isn't it?

  • physics - ,

    Janet jumps off a high diving platform with a horizontal velocity of 2.64 m/s and lands in the water 2.8 s later. How high is the platform? The acceleration of gravity is 9.8^2 m/s. Answer in units of m

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question