Homework Help: physics

Posted by Eddie on Wednesday, October 12, 2011 at 6:17pm.

Janet jumps off a high-diving platform with a horizontal velocity of 3.5 m/s and lands in the water 1.7 s later. How high is the platform, and how far from the base of the platform does she land?

Physics - Tony, Monday, September 24, 2012 at 12:33pm
When finding how high the platform is the horizontal velocity isn't important.
S= 1/2at^2 where S is the displacement and a is the acceleration due to gravity (9.8)
so
S=(1/2) (9.8) 1.7^2
S=4.9*1.7^2
S=14.161 meters

When finding how far from the base Janet lands use the formula:
D=Ut where D= the distance from the platform, U= the horizontal velocity, and t= time
So:
D=Ut
D=3.5*(1.7)
D=5.95
Simple isn't it?

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