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November 27, 2014

November 27, 2014

Posted by **Tina** on Wednesday, October 12, 2011 at 5:40pm.

(a) What is the tension in the cord?

(b) What is the speed of the ball?

- Physics -
**Damon**, Wednesday, October 12, 2011 at 5:50pmr = radius of circle = 1.4 sin 20

centripetal acceleration = v^2/r

horizontal force needed = m v^2/r

but

horizontal component of tension = T sin 20

vertical component of tension = T cos 20 = m g

so

T = m g/cos 20 = 2.61 Newtons (part A)

so

T sin 20 = m v^2/r = m v^2/1.4 sin 20

2.61 (1.4 )sin^2 20 = .25 v^2

solve for v

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