Posted by Tina on Wednesday, October 12, 2011 at 5:40pm.
r = radius of circle = 1.4 sin 20
centripetal acceleration = v^2/r
horizontal force needed = m v^2/r
but
horizontal component of tension = T sin 20
vertical component of tension = T cos 20 = m g
so
T = m g/cos 20 = 2.61 Newtons (part A)
so
T sin 20 = m v^2/r = m v^2/1.4 sin 20
2.61 (1.4 )sin^2 20 = .25 v^2
solve for v
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