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math

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farmer fred had chickens and cows on his farm. he knows that together there are 108 legs and 30 heads. how many of each type of animal does he have?

  • math - ,

    c chickens have 2c legs
    m cows have 4m legs

    c+m = 30
    2c + 4m = 108

    multiply the top equation by two, and subtract

    2c + 2m = 60
    2c + 4m = 108

    2m = 48
    m = 24
    c = 6

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