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A dynamite blast at a quarry launches a rock straight upward, and 1.5 s later it is rising at a rate of 19 m/s. Assuming air resistance has no effect on the rock, calculate its speed (a) at launch and (b)4.6 s after launch.

  • Physics -

    V = Vo - gt = +19 m/s at t = 1.5
    (a) Solve for Vo
    Vo = 19 + 9.8*1.5 = 33.7 m/s

    (b) Plug in t = 4.6 in the first formula and solve for V, which will be negative.

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