a worker pushing a wheelbarrow of mass 50 kg with a constant velocity along a horizontal surface whose coefficient of friction is 0.5 and the angle of force is 30 degree

To calculate the force required for a worker to push a wheelbarrow with a constant velocity along a horizontal surface, we need to consider the force of friction and the force applied by the worker at an angle.

First, let's calculate the force of friction using the coefficient of friction. The formula for friction force is:

Friction force = coefficient of friction * normal force

Since the wheelbarrow is on a horizontal surface, the normal force is equal to the weight of the wheelbarrow. The formula for weight is:

Weight = mass * acceleration due to gravity

Given that the mass of the wheelbarrow is 50 kg and the acceleration due to gravity is 9.8 m/s^2, we can calculate the weight:

Weight = 50 kg * 9.8 m/s^2 = 490 N

Now, substitute the value of the coefficient of friction (0.5) and the weight (490 N) into the friction force formula:

Friction force = 0.5 * 490 N = 245 N

The next step is to calculate the force applied by the worker at an angle. Since the worker is pushing the wheelbarrow with a constant velocity, the applied force should balance the opposing forces of friction and the component of weight along the inclined direction.

To find the component of weight along the inclined direction, we use the following formula:

Component of weight along inclined direction = weight * sin(angle)

Given that the angle is 30 degrees, we can calculate the component of weight:

Component of weight along inclined direction = 490 N * sin(30 degrees) = 245 N

Now, the force applied by the worker should be equal to the sum of the friction force and the component of weight along the inclined direction:

Force applied by worker = Friction force + Component of weight along inclined direction
= 245 N + 245 N
= 490 N

Therefore, the worker needs to apply a force of 490 Newtons at a 30-degree angle to push the wheelbarrow with a constant velocity along the horizontal surface.

That is neither a sentence nor a question.