How many moles are in 1.18g of 4.7x10^-4 M AgNO3?
moles = M x L
You don't have a volume listed.
To find out how many moles are in 1.18 g of AgNO3, you'll need to use the formula:
moles = mass / molar mass
First, let's calculate the molar mass of AgNO3 (silver nitrate). The molar mass can be found by adding up the atomic masses of all the atoms in the molecule:
AgNO3:
Ag (Silver) = 107.87 g/mol
N (Nitrogen) = 14.01 g/mol
O (Oxygen) = 16.00 g/mol (there are three oxygen atoms)
Now, let's calculate the molar mass of AgNO3:
Molar mass of AgNO3 = (107.87 g/mol) + (14.01 g/mol) + (16.00 g/mol × 3) = 169.87 g/mol
Next, we'll use the formula mentioned earlier to calculate the number of moles:
moles = mass / molar mass = 1.18 g / 169.87 g/mol
Now, substitute the values into the equation:
moles = 1.18 g / 169.87 g/mol
By performing this calculation, you will find the number of moles in 1.18 g of AgNO3.