Friday

December 19, 2014

December 19, 2014

Posted by **Lynn** on Wednesday, October 12, 2011 at 1:05am.

You are choosing between two long-distance telephone companies. Company A charges $.09 per minute plus $4 monthly fee. Company B charges $.11 per minute with no monthly fee.

X = number of minutes you call long distance

y = total cost of long distance phone service.

How am I suppose to write two equations representing the cost of each company's service for one month?

- Math - Word Problem -
**Steve**, Wednesday, October 12, 2011 at 4:35amJust take each sentence and figure out what is says algebraically.

Company A: for x minutes, the charge is 9x + 400 cents

Company B: for x minutes, the charge is 11x with no extra fee.

So, which company is cheaper? That obviously will depend on the number of minutes you use.

So, when will A charge more than B?

9x + 400 > 11x

400 > 2x

200 > x

So, if you use less than 200 minutes, A charges more.

At 200 minutes,

9*200 + 400 = 1800+400 = $22.00

11*200 = $22.00

If using more than 200 minutes, A only charges an extra 4 cents/min, while B charges 11 cents/min, so A will be cheaper.

**Answer this Question**

**Related Questions**

math - I need help forming an equation for this word problem.. A long distance ...

Algebra - 2. A long distance phone company has a monthly fee of $7.95 and ...

Algebra - Need help with these please--- 2. A long distance phone company has a ...

math - 23. There are two telephone companies provide home phone service in New ...

math - 23. There are two telephone companies provide home phone service in New ...

Math - the international links long-distance phone company charges no monthly ...

Math Word Problem SK - Customers of a phone company can choose between two ...

math - Telephone company A charges $3.00 for the first minute of any long ...

Algebra 1-Math - There's a table that says Company A charges $0.36 plus 0.03. ...

math - You need to choose a long distance telephone service for your business. ...