Assuming no air resistance, how long does it take a penny to fall if it was dropped from the CN Tower (553 m)? Acceleration due to gravity is 9.8 m/s2.
To determine the time it takes for a penny to fall from the CN Tower, we can use the equation:
h = (1/2) * g * t^2
where:
h = height (553 m)
g = acceleration due to gravity (9.8 m/s^2)
t = time
Rearranging the equation to solve for time, we have:
t^2 = (2 * h) / g
t = square root of [(2 * h) / g]
Plugging in the given values, we have:
t = √[(2 * 553) / 9.8]
Calculating the value, we get:
t ≈ √113.0612244897959
t ≈ 10.63014581273465
Therefore, it would take approximately 10.63 seconds for the penny to fall from the CN Tower if there is no air resistance.
To find out how long it takes a penny to fall from the CN Tower assuming no air resistance, we can use the basic equation of motion:
s = ut + (1/2)at^2
Where:
s = distance or height (553 m in this case)
u = initial velocity (0 m/s since the penny is dropped)
a = acceleration due to gravity (-9.8 m/s^2, negative because it is acting downwards)
t = time taken
Since the penny is dropped, its initial velocity is zero (u = 0). Therefore, the equation becomes:
s = (1/2)at^2
Plugging in the given values:
553 = (1/2)(-9.8)t^2
Simplifying the equation:
553 = -4.9t^2
To isolate t, divide both sides by -4.9:
t^2 = 553 / -4.9
t^2 ≈ -113.061
Since time cannot be negative, we discard the negative value. Therefore,
t ≈ √(-113.061)
The square root of a negative number is not a real number, so we cannot find an exact solution in this case. It appears that I have made an error or overlooked a detail. I apologize for the confusion. Let me recalculate using the correct method.