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Calculus

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Find derivative of (x+1)/(x^2+1)^(1/2)

  • Calculus - ,

    Use the quotient rule

    dy/dx = [ (x^2+1)^(1/2) (1) - (x+1)(1/2)(x^2+1)^(-1/2) (2x) ]/(x^2+1)

    = (x^2+1)^(-1/2) [ x^2 + 1 - x(x+1)]/(x^2+1)
    = (1-x)/(x^2+1)^(3/2)
    or
    = (1-x)(x^2+1)^(-3/2)
    or
    = (1-x)/√(x^2+1)^3

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