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December 17, 2014

December 17, 2014

Posted by **terra** on Tuesday, October 11, 2011 at 6:50pm.

I got to ln(f(x)) = 2^x(lnx) but now I'm stuck..

- calculus -
**Reiny**, Tuesday, October 11, 2011 at 7:31pma good start

I would change f(x) to y for easier typing

lny = (2^x)(lnx) , you had that

now use the product rule on the right side

y'/y = (2^x)(1/x) + (lnx)(ln2((2^x)

y' = y( (2^x)/x + ln2(lnx)(2^x))

= x^(2^x)) [ (2^x)/x + ln2(lnx)(2^x) ]

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