Posted by Anonymous on .
PERIMETER OF A RECTANGLE IS 32CM AND AREA IS 55CM FIND THE LENGHT.

trig 
Reiny,
l+w = 16 > l=16w
lw=55
w(16w)=55
16w  w^2=55
w^216w+55=0
(w5)(w11)=0w=5 or w=11
we have a symmetric solution, that is,
if w=5 , then l=11
if w=11, then l = 5
the rectangle is 5 by 11
usually the longer side is called the length
so the length is 11 cm