Posted by **Anonymous** on Tuesday, October 11, 2011 at 6:48pm.

PERIMETER OF A RECTANGLE IS 32CM AND AREA IS 55CM FIND THE LENGHT.

- trig -
**Reiny**, Tuesday, October 11, 2011 at 7:23pm
l+w = 16 --> l=16-w

lw=55

w(16-w)=55

16w - w^2=55

w^2-16w+55=0

(w-5)(w-11)=0w=5 or w=11

we have a symmetric solution, that is,

if w=5 , then l=11

if w=11, then l = 5

the rectangle is 5 by 11

usually the longer side is called the length

so the length is 11 cm

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