Homework Help: physics

Posted by Anonymous on Tuesday, October 11, 2011 at 6:40pm.

A block of mass 12.0 kg slides from rest down a frictionless 35.0° incline and is stopped by a strong spring with k = 4.00 104 N/m. The block slides 3.00 m from the point of release to the point where it comes to rest against the spring. When the block comes to rest, how far has the spring been compressed?

physics - drwls, Tuesday, October 11, 2011 at 8:19pm
Let the compression of the spring be x.

When the block comes to rest, the potential energy loss equals (1/2) k x^2

The P.E. loss is M*g*3.00 sin35 = 202.4 J

Solve
202.4 = (1/2)kx^2 for x.

Answer this Question

Related Questions

physics - A block of mass 12.0 kg slides from rest down a frictionless 35.0°...
college physics - A block of mass 12.0 kg slides from rest down a frictionless ...
physic - A block of mass 12.0 kg slides from rest down a frictionless 34.0° ...
physics - A block of mass m = 2.00 kg is released from rest at h = 0.400 m from...
PHYSICS - A 16 kg block slides down a 30 degree frictionless incline where it is...
Physics - A 4 kg block slides down a frictionless incline making an angle of 60&...
physics - A 0.50-kg block, starting at rest, slides down a 30.0° incline ...
physics - A 0.50-kg block, starting at rest, slides down a 30.0° incline ...
physics - Question Part Points Submissions Used 1 2 3 4 5 –/5 –/5 0/5...
Physics - A 6.0 kg block,starting from rest, slides down a frictionless incline ...

For Further Reading

First Name:
School Subject:
Answer: