Post a New Question


posted by .

A block of mass 12.0 kg slides from rest down a frictionless 35.0° incline and is stopped by a strong spring with k = 4.00 104 N/m. The block slides 3.00 m from the point of release to the point where it comes to rest against the spring. When the block comes to rest, how far has the spring been compressed?

  • physics -

    Let the compression of the spring be x.

    When the block comes to rest, the potential energy loss equals (1/2) k x^2

    The P.E. loss is M*g*3.00 sin35 = 202.4 J

    202.4 = (1/2)kx^2 for x.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question