Posted by Anonymous on .
A block of mass 12.0 kg slides from rest down a frictionless 35.0° incline and is stopped by a strong spring with k = 4.00 104 N/m. The block slides 3.00 m from the point of release to the point where it comes to rest against the spring. When the block comes to rest, how far has the spring been compressed?
Let the compression of the spring be x.
When the block comes to rest, the potential energy loss equals (1/2) k x^2
The P.E. loss is M*g*3.00 sin35 = 202.4 J
202.4 = (1/2)kx^2 for x.