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show that the equivalence amount of citric acid for 1.00g of sodium bicarbonate is 0.76g

  • chemitry -

    1/84 = moles in 1.0 g NaHCO3 OR equivalents in 1.0 g NaHCO3.

    (1/84) x (192.12g citric acid/mol) = moles citric acid.
    equivalents citric acid = moles citric acid/3 or
    (1/84) x (192.12 g/mole) x (1/3) = ?

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