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October 25, 2014

October 25, 2014

Posted by **tara** on Tuesday, October 11, 2011 at 3:58pm.

- elements of calculus -
**Steve**, Tuesday, October 11, 2011 at 4:45pmUsing the quotient rule:

s = √t / (3t-1)

s' = [1/(2√t) * (3t-1) - √t(3)]/(3t-1)^2

= [(3t-1)/(2√t) - 3√t]/(3t-2)^2

= [3t-1 - 6t]/[2√t (3t-2)^2]

= -(3t+1)/[2√t (3t-2)^2]

or, using the product rule:

s = √t * (3t-1)^-1

s' = 1/(2√t) * (3t-1)^-1 - 3√t * (3t-1)^-2

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