Posted by **tara** on Tuesday, October 11, 2011 at 3:55pm.

write the equation of the line tangent to the curve y= 3x^3- 2x at the point where x=2

- elements of calculus -
**bobpursley**, Tuesday, October 11, 2011 at 4:29pm
y'= 9x^2-2 which is the slope,

y'=34 at x=2

y= mx+b

y=34x+b

now at x=2, y= 3*8-4=22

22=34*2+b solve for b, and you have the equation of the tangent.

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