Posted by **ashley** on Tuesday, October 11, 2011 at 1:54pm.

A 75.0-W lamp is placed in series with a resistor and a 120.0-V source. If the voltage across the lamp is 24 V, what is the resistance R of the resistor?

- physics -
**drwls**, Tuesday, October 11, 2011 at 3:09pm
The voltage drop across the resistor is 120 - 24 = 96 V

The resistance R' of the lamp can be derived from its Wattage at 120 V:

75 W = V^2/R' = 14400/R'

R' = 192 ohms

Since the lamp gets 24/120 = 20% of the voltage drop, the other 80% of the voltage (96 V) is across the resistor.

With both in series, circuit current = lamp current = 24 V/192 ohms = 0.125 Amps

Resistor resistance = V(resistor)/I

= 96/(1/8) = 768 ohms

- physics -
**Henry**, Monday, May 4, 2015 at 10:13pm
Vr = 120-24 = 96 V. = Voltage across the

resistor.

V*I = 75W.

24I = 75

I = 3.125A = Lamp current

R = Vr/I = 96/3.125 = 30.72 Ohms in series with lamp.

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