Posted by ashley on Tuesday, October 11, 2011 at 1:09pm.
A golf ball is hit with an initial velocity of 50 m/s at an angle of 45° above the horizontal. How far will the ball travel horizontally before it hits the ground?

physics  Henry, Wednesday, October 12, 2011 at 7:06pm
Vo = (50m/s,45deg.).
Xo = hor. = 50cos45 = 35.36m/s.
Yo = ver. = 50sin45 = 35.36m/s.
t(up) = (Vf  Yo) / g,
t(up) = (0  35.36) / 9.8 = 3.61s.
t(dn) = t(up) = 3.61s.
T = t(up) + t(dn)=3.61 + 3.61=7.22s. =
Time in flight.
Dh = Xo * T = 35.36 * 7.22 = 255m. =
Hor. distance.
Alternate Method:
Dh = Vo^2 * sin2A / g.
A = 45 deg.
Vo = 50m/s.

physics  Anonymous, Wednesday, December 5, 2012 at 9:38am
hyt
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