Posted by **Ivo** on Tuesday, October 11, 2011 at 12:25am.

An electric motor is used to pull a 125 kg box across a floor using a long cable. the tension in the cable is 350N and the box accelerates at 1.2m/s^2[forward] for 5.0s. The cable breaks and the box slows down and stops.

b) How far does the box travel up to the moment the cable breaks?

c)How far does the box travel from the moment the cable breaks until it stops?

- Physics -
**drwls**, Tuesday, October 11, 2011 at 9:06am
a) (1/2) a t^2, where

a = 1.2 m/s^2

t = 5.0 s

b) Speed at cable breakage = a t

V' = 6 m/s

Let distance travelled after cable breakage be X.

M g X *Uk = (M/2) V'^2

You need the coefficient of kinetic friction Uk. You can get it from the initial cable tension, before it breaks.

350 - M*g*Uk = M*a

Uk = (350 - M a) /(Mg)

= 0.163

Now solve for X.

## Answer This Question

## Related Questions

- Physics - An electric motor is used to pull a 125 kg box across a floor using a ...
- Physics - An electric motor is used to pull a 125 kg box across a floor using a ...
- physics - an electric motor is used to pull a 125 kg box across a floor using a ...
- Physics - an electric motor is used to pull a 125 kg box across a floor using a ...
- Physics - A crane is lowering two boxes downward at a constant velocity. The ...
- PHYSICS - a 107 KG BOX ON THE RIGHT AND A 43 KG BOX ON THE LEFT ARE TIED ...
- PHYSICS - A 107 kg bix on the right and a 50 kg box on the left are tied ...
- Physics - A box of sand (initially at rest) is pulled along a horizontal floor ...
- Calculus - An electric elevator cable with a motor at the top has a multistrand ...
- Physics - A 1,500 kg crate hangs motionless from a crane cable. What is the ...

More Related Questions