Studies have shown a particular television commercial is understood by 25% of first grade students and 80% of fourth grade students. If a television advertising agency randomly selects one first grader and one fourth grader, what is the probability neither child would understand the commercial, assuming the children's reactions are independent?

The probability that both/all events would occur is found by multiplying the probabilities of the individual events.

(1-.25)(1-.80) = ?

what is the factor of 8 and 16

10

Is 2,340 divisible by 90? How do you know?

5464

To find the probability that neither child would understand the commercial, we can calculate the probability that each child individually does not understand the commercial and then multiply these probabilities together.

Let's denote the event that a first grader understands the commercial as A1, and the event that a fourth grader understands the commercial as A4.

The probability that a first grader does not understand the commercial is 1 - 0.25 = 0.75 (since the percentage who understood is given as 25%).

Similarly, the probability that a fourth grader does not understand the commercial is 1 - 0.80 = 0.20 (since the percentage who understood is given as 80%).

Since the reactions of the first grader and fourth grader are assumed to be independent, we can multiply the probabilities:

P(neither child understands) = P(not A1) * P(not A4)
= 0.75 * 0.20
= 0.15

Therefore, the probability that neither child would understand the commercial is 0.15 or 15%.