Monday

September 1, 2014

September 1, 2014

Posted by **tibby** on Monday, October 10, 2011 at 11:24pm.

Someone help please. I've tried two different approaches to this problem which were done by other students also and it worked for the same question but with different numbers. I've used this formula

x= horizontal distance of cannon from target y= meters above the cannon

g= 9.8 u= cannon's muzzle speed

r= unknown a= angle at which cannon should be fired

b= theta

--------------------------------

r = sqrt(x^2+y^2)

cos(b)= x/r

r*sin(2a-b)=(9.8*2^2)+y

i got 62.429 degree

and the second method used was this formula

h=(v^2sin^2theta)/2(9.8)

and i've gotten 11.643 degree

both of them are wrong, please help :(

Due tonight at 12am

- physics -
**tibby**, Monday, October 10, 2011 at 11:46pmnvm there was a arithmetic error

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