Posted by Jade on Monday, October 10, 2011 at 9:51pm.
If f and g are functions of x
d/dx(f/g) = (f'g - fg')/g^2
This is just a variation of the well-loved product rule, where f/g = f * g^-1
d/dx(f * g^-1) = f'*g^-1 + f*(-1)g^-2 * g'
= f'/g - fg'/g^2
= (f'g - fg')/g^2
Related Questions
Calculus - f(x)=5+(6/x)+(7/x^2), find f'(x). I haven't done fractions ...
Calculus - How do I use the chain rule to find the derivative of square root(1-x...
Calculus - Let f(x)= 5x ------- x–2 are we supposed to use the quotient ...
Calculus - y= [(x-3)/(x^2+1)]^2 find the derivative. I know i would start off ...
Calculus - y= [(x-3)/(x^2+1)]^2 I know that I would use the product rule on the ...
calculus - Differentiate: 1/s+ke^s Do I just use the quotient rule? Thanks
calculus - Hey I am working on differentiation/quotient rule for this problem...
calculus - Please help, I have no idea where to start. Use the quotient rule to ...
calculus - Please help. Applying the chain rule, how do I find the derivative of...
Calculus - Find the derivative of y with respect to x. y= (lnx)/(3+4lnx) Should ...
For Further Reading
