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November 27, 2014

November 27, 2014

Posted by **Jade** on Monday, October 10, 2011 at 9:51pm.

- Calculus -
**Steve**, Tuesday, October 11, 2011 at 12:12amIf f and g are functions of x

d/dx(f/g) = (f'g - fg')/g^2

This is just a variation of the well-loved product rule, where f/g = f * g^-1

d/dx(f * g^-1) = f'*g^-1 + f*(-1)g^-2 * g'

= f'/g - fg'/g^2

= (f'g - fg')/g^2

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