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March 3, 2015

March 3, 2015

Posted by **Sejul** on Monday, October 10, 2011 at 2:35pm.

- math -
**bobpursley**, Monday, October 10, 2011 at 3:30pmvolume= l*w*h

2h+w=35 or w=35-2h

2h+l=35 or l= 35-2h

volume= (35-2h)(35-2h)h

dV/dh= 2(35-2h)(-2)h+ (35-2h)^2 =0

4h=35-2h

6h=35

solve for h, then the cut squares are hxh.

- math -
**Steve**, Monday, October 10, 2011 at 3:35pmhen the corners of size x are cut out, the dimensions of the box are

35-2x and 35-2x and x, and the volume is thus

v = (35-2x)(35-2x)x

= 1225x - 140x^2 + 4x^3

dv/dx = 1225 -280x + 12x^2

dv/dx = 0 when x = 5.83333

- calculus -
**lulu**, Friday, November 18, 2011 at 1:29aman open box is to be made from a piece of metal 16 by 30 inches by cutting out squares of equal size from the corners and bending up the sides. what size should be cut out to create a box with the greatest volume? what is the maximum volume?

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