Homework Help: math

Posted by BK on Monday, October 10, 2011 at 1:55pm.

ball thrown up from top of 96 foot high tower with initial velocity of 80 ft/s.

when does ball reach max height and how high is it at that time?

math - Steve, Monday, October 10, 2011 at 3:22pm
v = 80 - 32t
v = 0 is where the ball stops rising and starts falling

0 = 80 - 32t
t = 2.5s

h = 96 + 80t - 16t^2
= 96 + 80*2.5 - 16*6.25
= 196 ft
math - Anissa, Monday, October 10, 2011 at 3:52pm
what is the -32 t? I think I undersaand the rest.

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