Posted by Anissa on .
Find the max or min value for y given the restictions on x.
y= x^3 x^2 6x
a) 0<x<3 min
b) 2<x<0 max

algebra 
Anissa,
what is tttt?

algebra 
Steve,
y = x^3  x^2  6x = 0(x+2)(x3)
y' = 3x^2  2x  6
y' = 0 at approximately 1.7, 1.1 (1 + sqrt(19))/3.
Knowing what we do about the shape of cubics, we can say that a local max is at x=1.1, and a local min is at x=1.7
Note how the given intervals correspond to exactly one "hump" of the graph, so the local min/max is the min/max for that interval. 
algebra 
Anissa,
I don't understand the y' stuff. I'm only in algebra. Is there another way?

algebra 1 
toria,
how do u convert 63 yards into ft