Saturday

January 31, 2015

January 31, 2015

Posted by **vicki** on Monday, October 10, 2011 at 1:29pm.

- calculus -
**Steve**, Monday, October 10, 2011 at 2:47pmHere goes:

F(x) = f(xf(xf(x)))

F'(x) = f'(xf(xf(x))) * (xf(xf(x)))'

= f'(1*f(1*f(1))) * (xf(xf(x)))'

= f'(f(2)) * (xf(xf(x)))'

= f'(3) * (xf(xf(x)))'

= 6 * (xf(xf(x)))'

= 6 * (f(xf(x)) + xf'(xf(x)))

= 6 * (f(2) + xf'(2))

= 6 * (3 + 5)

= 6*8

= 48

Any other takers? Did I miss a step somewhere?

- calculus -
**Mgraph**, Monday, October 10, 2011 at 3:26pmF(x) = f(xf(xf(x)))

F'(x) = f'(xf(xf(x))) d/dx xf(xf(x))

F'(x) = f'(xf(xf(x))) [ f(xf(x)) + xf'(xf(x)) d/dx xf(x) ]

F'(x) = f'(xf(xf(x))) [ f(xf(x)) + xf'(xf(x)) [f(x) + xf'(x)] ]

F'(1) = f'(1*f(1*f(1))) [ f(1*f(1)) + 1*f'(1*f(1)) [f(1) + 1*f'(1)] ]

F'(1) = f'(f(f(1))) [ f(f(1)) + f'(f(1)) [f(1) + f'(1)] ]

F'(1) = f'(f(2)) [ f(2) + f'(2) [2 + f'(1)] ]

F'(1) = 6 [ 3 + 5 [2 + 4] ]

F'(1) = 6 [ 3 + 5 *6 ]

F'(1) = 6 [ 3 + 30 ]

F'(1) = 6 [ 33 ]

F'(1) = 196

**Answer this Question**

**Related Questions**

Pre-Calculus/Calculus - I am too embarassed to ask this Calculus (really pre-...

Math:Calculus - Use the Fundamental Theorem of Calculus to find the derivative ...

Calculus Help - Use calculus to find the area A of the triangle with the given ...

math, calculus 2 - Use part 1 of the Fundamental Theorem of Calculus to find ...

Calculus - The area is bounded by y= x^3, x= 2 is rotated around the x-axis. ...

Calculus - A curve is defined by the parametric equations: x = t2 – t and y = t3...

COLLEGE CALCULUS. HELP! - the fundamental theorem of calculus, f(x)=∫(0,x...

calculus - Find the arc length of the graph of y = x from x = 0 to x = 3 using ...

Calculus AP need help! - Use Part 1 of the Fundamental Theorem of Calculus to ...

Calculus 1 - Use the fundamental theorem of calculus to find the area bounded by...