Posted by **Anonymous** on Monday, October 10, 2011 at 10:47am.

In the triangle ABC ,AB=11 cm ,BC=9cm an CA=10 cm..Find area of the triangle ABC

- math -
**Steve**, Monday, October 10, 2011 at 12:29pm
If you don't have access to heron's formula, then you can use law of sines

sin a/9 = sin b/10 = sin c/11

c = 180-(a+b)

work on that a while and you will find sin b = .8578

Now, h/9 = sin b

so h = 9 sin b

area = 1/2 * 11 * 9 * .8578 = 42.46

Heron's formula says that

with s = (a+b+c)/2

area = sqrt(15*4*5*6) = 42.43

looks good to me.

- math -
**Anonymous**, Monday, December 9, 2013 at 2:06pm
WROOOOOONG

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