Posted by **Suzy** on Monday, October 10, 2011 at 9:43am.

The driver of a 1600 kg car, initially traveling at 10.6 m/s, applies the brakes, bringing the car to rest in a distance of 23.0 m.

(a) Find the net work done on the car.

(b) Find the magnitude and direction of the force that does this work. (Assume this force is constant.)

- College Physics -
**bobpursley**, Monday, October 10, 2011 at 9:54am
a) net work equals the change in KE.

or, Vf^2=Vi^2+2ad solve for a

then work= force*distance= mass*a*distance.

b) force= ma

- College Physics -
**Kellie**, Monday, October 10, 2011 at 12:19pm
I worked out the first equation for part a and found the acceleration to be -0.2304. When doing the second equation, I found work to be -8478.72 J. Can work be negative? I feel like I haven't worked this out correctly.

- College Physics -
**Kellie**, Monday, October 10, 2011 at 12:21pm
I feel like the acceleration isn't correct.

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