Posted by abbie on .
(a) What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 8.86 m/s when going down a slope for 3.30 s? (b) How far does the skier travel in this time?
a. a = (Vf - Vo) / t,
a = (8.86 _ 0) / 3.3 = 2.68m/s^2.
b. d = Vo + 0.5a*t^2,
d = 0 + 1.34*(3.3)^2 = 14.62m.