Friday

February 27, 2015

February 27, 2015

Posted by **Erica** on Monday, October 10, 2011 at 2:27am.

x = (y-1)² - 1, x = (y-1)² + 1 from y=0 to y=2.

I graphed the two functions and the do not intersect? Does it matter? Or do I still find the area in between?

Thank you!

- Calc -
**MathMate**, Monday, October 10, 2011 at 8:56amYou're right, unless you have made a typo, the two curves will never intersect.

As you said, it does not matter, the lines y=0 and y=2 will intersect both lines to make a curved rectangle whose area you'd have to calculate. The result should be a nice integer.

- Calc -
**Reiny**, Monday, October 10, 2011 at 8:59amEven though they don't intersect, there is the area bounded between y=0 and y=2

Did you notice that the two parabolas are congruent and the second is merely translated 2 units to the right?

so the horizontal distance between corresponding points is always 2

that is x2-x1 = (y-1)^2 + 1 - ((x-1)^2 - 1) = 2

Area = ∫x dy from 0 to 2

= ∫ 2dy from 0 to 2

= [2y] from 0 to 2

= 4-0 = 4

check my thinking, seems too easy.

**Answer this Question**

**Related Questions**

Calculus - 1. Find the area of the region bounded by the curves and lines y=e^x ...

Calc - y = x^2 y = 6 - x Find the area of the region by integrating (a) with ...

Calc - y = x^2 y = 6 - x Find the area of the region by integrating (a) with ...

Calculus - We're learning disks, shells, and cylinders in school but we have a ...

Calculus - We're learning disks, shells, and cylinders in school but we have a ...

calculus - find the area of one of the regions bounded by the curves y=sin x and...

math - how do i use the shell method to find the volumes of the solids generated...

calculus - set up sums of integrals that can be used to find the area of the ...

Analytic Geometry - Circles and Areas - Let R denote the circular region bounded...

Calculus AB - y=6-x y=x^2 Find the area of the region by integrating with ...